24x^2-50x+21=0

Solution for 24x^2-50x+21=0 equation:

24x^2-50x+21=0

a = 24; b = -50; c = +21;
Δ = b2-4ac
Δ = -502-4·24·21
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-22}{2*24}=\frac{28}{48}
=7/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+22}{2*24}=\frac{72}{48}
=1+1/2
$